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Module 2: Foundations in biology›Enzymes (2.1.4)

Enzymes (2.1.4)

An overview of enzymes (2.1.4) from OCR A level Biology including: the mechanisms of enzyme action, factors affecting enzyme activity and enzyme inhibition
16 min

Enzymes are a type of globular protein. They have a specific 3-dimensional shape as a result of their primary structure (sequence of amino acids).

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Activation energy is the energy needed to start a reaction.

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Enzymes act as biological catalysts, lowering the activation energy required for a reaction to occur by forming weak interactions with the substrate. These interactions can strain the bonds in the substrate, making them more likely to break or form.

Enzymes are not altered or used up during a reaction; they can be reused.

The graph shows free energy on the y-axis and reaction progress on the x-axis. Two curves are depicted: a red curve labeled 'Without enzyme' and a blue curve labeled 'With enzyme'. Both curves start from a similar energy level labeled 'reactants'. The red curve reaches a higher peak compared to the blue curve, indicating higher activation energy. Annotations indicate 'Activation energy without enzyme' for the red curve and 'Activation energy with enzyme' for the blue curve. Both curves decline to a lower energy level labeled 'products', with an annotation 'Total energy released by the reaction'.
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In cells, many metabolic reactions have high activation energies and would occur too slowly at normal biological temperatures. Enzymes lower the activation energy, allowing reactions to proceed quickly and efficiently, supporting life without raising the cell’s temperature.

Enzymes play a crucial role in regulating metabolism, determining structures and functions from the cellular to the whole organism level.

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Enzymes catalyse anabolic reactions where large molecules are synthesised from their component parts.

For example, enzymes are involved in synthesising structural components, such as:

  • Cellulose: Enzymes join together beta-glucose monomers to form the cellulose polymer to build plant cell walls.
  • Muscle fibres: Enzymes join amino acid monomers together to form the proteins (such as actin and myosin) that assemble into muscle filaments.
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Enzymes catalyse catabolic reactions where large molecules are broken down into smaller molecules. These reactions usually release energy (and the end-products can be used in respiration to produce ATP).

For example, the enzyme amylase catalyses the hydrolysis (breakdown) of starch into maltose.
Without enzymes catalysing catabolic reactions, large molecules in our food would not be broken down or energy released at a rate fast enough to support life.

The image is a diagram showing the process of anabolic and catabolic reactions involving enzymes. It is divided into two columns. The left column depicts anabolic reactions, and the right column depicts catabolic reactions. Each column is divided into three stages: Before reaction, During reaction, and After reaction. In the anabolic reactions column, 'Before reaction' shows a green and blue substrate approaching an enzyme with an active site labeled. 'During reaction' shows the substrates bound to the enzyme. 'After reaction' shows a single product released from the enzyme. In the catabolic reactions column, 'Before reaction' shows a purple substrate approaching an enzyme. 'During reaction' shows the substrate bound to the enzyme. 'After reaction' shows the substrate split into two products, one green and one blue, released from the enzyme. Both enzymes are illustrated in pink, and the substrates and products are in green, blue, and purple. Each stage is connected by downward arrows indicating progression.
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Enzymes are essential for various biochemical processes and can function both inside cells (intracellular) and outside cells (extracellular).

Intracellular enzymes function within cells, catalysing numerous metabolic processes essential for cell survival and function.

Catalase is an example of an intracellular enzyme and is found in nearly all living organisms that respire aerobically. It decomposes hydrogen peroxide, a harmful byproduct of aerobic metabolism, into water and oxygen:

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Extracellular enzymes are secreted by cells to function outside of the cell. They play crucial roles in digestion, where large nutrient molecules need to be broken down or modified outside the cell.

For example, amylase is an enzyme produced by cells in the salivary glands and pancreas. When released into saliva, it catalyses the hydrolysis of starch (a polysaccharide) into maltose (a disaccharide).

Diagram illustrating the breakdown of polymers by enzymes. At the top, a polymer, depicted as a chain of blue spheres, is being broken down by an extracellular enzyme, shown as a pink oval surrounding part of the polymer chain. Arrows indicate the direction of the breakdown, resulting in separate blue spheres labeled 'Monomers.' Below, inside a shaded rectangular area labeled 'Cell,' intracellular enzymes, represented as a pink shape, continue to break down the polymer into smaller pieces. Arrows point to a separate enzyme depicted as a pink shape with a glowing center, further processing these pieces. The diagram is labeled with 'Polymer,' 'Extracellular enzyme,' 'Monomers,' 'Intracellular enzymes,' and 'Cell.'
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Enzymes are globular proteins with a specific tertiary (3-dimensional) structure. An area within this structure, called the enzyme’s active site, is where substrates bind, forming an enzyme–substrate complex.

The shape of an enzyme’s active site is complementary to the substrate(s) involved in the specific reaction it catalyses.

Diagram showing an enzyme-substrate interaction process. On the left, a pink shape labeled 'Enzyme' with a groove labeled 'Active site' is shown. A purple puzzle-piece-like shape labeled 'Substrate' is positioned above the active site with an arrow pointing towards it, indicating that the substrate enters the enzyme's active site. Below this, the text reads 'The substrate enters enzyme’s active site'. On the right, the substrate is shown fitting into the enzyme, forming what is labeled as 'The enzyme-substrate complex'. An arrow points from the left diagram to the right, indicating the progression of the interaction.
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The lock-and-key hypothesis of enzyme action suggests that a substrate fits into the rigid structure of an enzyme’s active site precisely, in the same way a specific key fits into its corresponding lock.

When an enzyme and its substrate collide, the side chains of amino acids (R groups) within the enzyme’s active site form temporary bonds with the substrate. This results in the formation of an enzyme–substrate complex.

The enzyme catalyses the reaction, and the products are formed in an enzyme–product complex. The enzyme then releases the products and is left unchanged, ready to be reused.

The image illustrates the lock-and-key model of enzyme activity. At the top, the title 'The lock-and-key model' is shown. Below this, a purple substrate shape is labeled 'Substrate fits exactly into the active site' and is pointing to a pink shape labeled 'Enzyme'. The substrate fits into an indented area on the enzyme. An arrow points down to the next stage labeled 'Enzyme-substrate complex', where the substrate is shown fitting perfectly into the enzyme. Another arrow points down to the next stage labeled 'The reaction occurs and enzyme-product complex is formed', where the substrate has changed colors, with a new green section. Finally, an arrow points down to the last stage where the enzyme is unchanged, but the substrate has split into two products: a green rectangle and a blue shape, labeled 'Products'. The enzyme retains its original shape. © Medify is noted at the bottom.
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The induced fit model of enzyme action suggests that enzymes are flexible and can change shape in the presence of a substrate. These changes in shape are known as conformational changes.

As an enzyme and substrate collide, the side chains of amino acids (R groups) within the enzyme’s active site form temporary bonds with the substrate. These weak interactions induce a change in the enzyme’s tertiary structure, strengthening the binding in the enzyme–substrate complex. This strains the bonds in the substrate making them easier to break (lowering the activation energy required for the reaction).

The products are formed within an enzyme–product complex and are then released. The enzyme returns to its original shape, ready to be reused.

The image illustrates the induced fit model of enzyme action in four stages. At the top, the label reads 'The induced fit model'. The first stage shows a pink, irregularly shaped enzyme with a concave opening, and a purple substrate with a complementary shape labeled 'Substrate'. An arrow points to the second stage, where the substrate fits into the enzyme, forming the 'Enzyme-substrate complex'. The third stage shows the enzyme changing shape to fit the substrate, labeled 'The enzyme's active site moulds to the shape of the substrate'. The final stage shows the enzyme-product complex, with the enzyme returning to its original shape as the products, a green and a blue section, are released. This stage is labeled 'The reaction occurs and enzyme-product complex is formed'. Arrows indicate the release of 'Products'. At the bottom, the copyright note © Medify is visible.
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The progress of enzyme-catalysed reactions can be investigated by:

  • Measuring the rate of product formation
  • Measuring the rate of substrate disappearance.
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The rate of an enzyme-catalysed reaction can be measured from a graph of the amount of product formed or substrate used through time.

The gradient of the curve at any given point is equal to the rate of the reaction (units are always ‘per unit time’). This changes over time if the relationship is curved.

A graph displaying 'Product formed, e.g. volume of O2 produced (cm³)' on the vertical axis and 'Time (s)' on the horizontal axis, with time values ranging from 0 to 300 seconds at intervals of 30. A red curve is plotted, starting at the origin and leveling off as time increases. A black dot labeled 'X' is on the curve. An annotation shows 'Rate of reaction = a/b' with dashed lines indicating 'a' vertically and 'b' horizontally from point 'X'.
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The maximum rate of a reaction is . This is when the maximum number of enzyme–substrate complexes have formed.

can be increased by increasing the enzyme concentration or increasing the temperature of the reaction.

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To investigate the effect of pH on enzyme activity, we can use the enzyme amylase to break down starch into maltose. The progress of the reaction is monitored using iodine as an indicator (iodine = yellow-brown; starch + iodine = blue-black).

Buffer solutions have a specific pH and maintain it, even if the reaction taking place would otherwise cause the pH of the reaction mixture to change.

Experimental procedure:

  1. Place drops of iodine indicator solution (potassium iodide) into the wells of a spot plate.
  2. Label a test tube with the buffer solution being used (pH levels to be tested).
  3. Add of amylase solution to each test tube.
  4. Add of the buffer solution to the amylase using a syringe.
  5. Add of starch solution to the mixture, start the stopwatch, and mix.
  6. Every 10 seconds, place a drop of the mixture onto a drop of iodine indicator solution on the spot plate.
  7. Note the time when the iodine indicator no longer turns blue-black, suggesting that the starch has completely broken down. The faster the iodine indicator stops turning blue-black, the more effective the enzyme is at that pH.
  8. Repeat for different buffer solutions (pH values).
A step-by-step procedure for a scientific experiment involving iodine and starch. Step 1: 'Add iodine to spot plate' is shown with a spot plate containing multiple wells filled with iodine, labeled 'Spot plate' and 'Iodine', with a dropper adding iodine. Step 2: 'Add amylase and buffer to a test tube, mix, and then add starch solution' is illustrated with a test tube containing 'Amylase solution (2 cm³)', 'Buffer solution (1 cm³, pH7)', and 'Starch solution (2 cm³)' being added. Step 3: 'Start stopwatch, wait 10 seconds' shows two stopwatches, one at 00:00 and the other at 00:10. Step 4: 'Add a drop of starch/amylase solution to a spot on the plate' displays a pipette adding a blue solution to the spot plate. Step 5: 'Repeat every 10 seconds until iodine doesn’t change colour' is represented with a spot plate labeled with times: '10s', '20s', '30s', '40s', '50s', and '60s', with the 50s spot in red. Step 6: 'Repeat the experiment for different pH values' shows three spot plates labeled 'pH 5 = 80 seconds', 'pH 9 = 90 seconds', and 'pH 14 = No reaction', with some wells in blue or red. © Medify
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Enzymes work best at their optimum pH (concentration of ions). Reactions will slow as the pH is increased or decreased away from the optimum.

ions interact with the hydrogen and ionic bonds forming an enzyme’s tertiary structure. Outside the enzyme’s optimal pH ([] is too high or too low), they can disrupt this bonding, altering the shape of the enzyme and its active site. When the shape of the active site is no longer complementary to the substrate, the enzyme is denatured, and it cannot function.

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To investigate the effect of temperature on enzyme activity, we can use the enzyme catalase which breaks down hydrogen peroxide into water and oxygen.

Experimental procedure:

  1. Cut a set weight of raw potato.
  2. Set up the equipment, as shown below.
  3. Add the potato to the hydrogen peroxide, start the timer, and mix.
  4. Record the volume of oxygen produced every 10 seconds.

Repeat this procedure with the same weight of potato that has been boiled for 10 minutes.

The diagram depicts a setup for collecting oxygen gas. On the left, a conical flask contains hydrogen peroxide and potato pieces, labeled as the catalase source. The flask is sealed with a bung, which connects to a tube labeled 'Tube (glass or rubber).' The tube carries the 'Oxygen flow' from the flask to the right side of the diagram. On the right, a measuring cylinder is inverted in a water-filled container. The water prevents air from entering the measuring cylinder during oxygen collection. The measuring cylinder is labeled with 'Volume of oxygen collected.'
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Temperature affects the speed at which molecules move and, therefore, the rate at which enzyme and substrate molecules collide.

Enzymes have an optimum temperature, where they catalyse reactions fastest. This is the temperature at which the maximum number of enzyme–substrate complexes form.

At low temperatures, molecules have less kinetic energy and move more slowly. This leads to fewer successful collisions between enzymes and substrates. As a result, fewer enzyme–substrate complexes form and the reaction rate is slower.

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Higher temperatures provide more kinetic energy. This results in more frequent and successful collisions between enzymes and substrates, accelerating the reaction.

Beyond the optimum temperature, too much kinetic energy breaks the hydrogen and ionic bonds that maintain the enzyme’s tertiary structure and shape the active site. The enzyme is said to be denatured. If the enzyme cannot bind the substrate, it cannot catalyse the reaction and the reaction rate drops sharply.

Denaturation is often irreversible.

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Diagram illustrating enzyme activity under different conditions. The top left shows a substrate labeled 'Substrate' approaching an enzyme labeled 'Enzyme'. An arrow labeled 'Optimum temperature and pH' points downward to the substrate binding into the enzyme’s active site with a starburst symbol, labeled 'The substrate binds into the enzyme’s active site'. Another arrow points downward to the enzyme releasing products with a green and blue shape, labeled 'Reaction proceeds as normal and products are formed'. On the right, an arrow labeled 'Extreme temperature or pH' points downward to a denatured enzyme labeled 'Denatured enzyme' with a red cross between the enzyme and substrate, labeled 'The shape of the enzyme’s active site is no longer complementary to the substrate's shape.' Another arrow points downward to a red cross labeled 'No reaction occurs'.
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The temperature coefficient is a measure of the change in the rate of a reaction after increasing the temperature by .

is calculated using the formula:

where:
is the initial temperature.

For most enzyme-catalysed reactions, values typically range between 2 and 3. This means the rate of reaction roughly doubles or triples with every rise in temperature.

The relationship does not apply outside of an enzyme’s optimum temperature range.

The graph displays 'Rate of reaction (arbitrary units)' on the y-axis and 'Temperature (°C)' on the x-axis. The y-axis ranges from 0 to 45, while the x-axis ranges from 0 to 80. Data points are plotted at approximately (0, 0), (20, 10), (30, 20), peaking at (40, 45), and decreasing through (60, 25) and (70, 10), ending at (80, 0). Dashed lines highlight points at (20, 10) and (30, 20). Annotations include 'Q10 = 20/10', 'Q10 = 2', and '(reaction rate doubles with a 10 °C increase in temperature)'. Additional labels show '20 °C' and 'T + 10 °C' below the x-axis at 20 and 30, respectively. The image is © Medify.
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Serial dilutions are useful for testing the impact of substrate or enzyme concentration on reaction rate. This dilution technique is used to produce a series of solutions with progressively lower concentrations.

Diagram showing a serial dilution of a 1% starch solution with a dilution factor of 10. Each solution is ten times less concentrated than the previous one. Starting with a stock solution of 10 cm³ of 1% starch solution: the first tube shows 1% concentration, followed by the addition of 9 cm³ of water for each subsequent tube. The second tube contains 0.1% concentration (1/10), the third tube 0.01% (1/100), the fourth tube 0.001% (1/1000), the fifth tube 0.0001% (1/10000), and the sixth tube 0.00001% (1/100000). Each tube shows the volume transferred as 1 cm³.
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To investigate the effect of substrate concentration on enzyme activity, we can use the enzyme catalase, which breaks down hydrogen peroxide (the substrate) into water and oxygen.

Experimental procedure:

  1. Prepare test tubes containing different concentrations of hydrogen peroxide.
  2. Set up the experiment with a conical flask fitted with a bung and glass tube leading to an upturned measuring cylinder filled with water.
  3. Place the source of catalase into the conical flask.
  4. Pour in one of the test tubes of hydrogen peroxide, start a timer, and mix.
  5. Record the volume of oxygen produced every 10 seconds.

Repeat the above procedure for all concentrations of hydrogen peroxide, recording your results.

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Initially, increasing substrate concentration increases the rate of reaction. With more substrate molecules present, the chance of forming enzyme–substrate complexes increases.

The rate of reaction subsequently plateaus as all active sites become saturated. The rate of reaction reaches its maximum . Beyond this point, further increase in substrate concentration will not increase the reaction rate, as there are no free active sites for additional substrate molecules to bind to. The enzyme concentration becomes the limiting factor in the reaction.

A graph with the x-axis labeled 'Substrate concentration' and the y-axis labeled 'Rate of reaction'. A red curve is shown starting at the origin, increasing steeply, then leveling off as it approaches a horizontal dotted line labeled 'Vmax'. An annotation near the curve's initial rise states, 'Rate of reaction increases proportionally to substrate concentration'. Another annotation near the flat part of the curve states, 'All substrate molecules have bound to active sites. Increasing substrate concentration does not affect reaction rate'.
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To investigate the effect of enzyme concentration on enzyme activity, we can use the enzyme catalase which breaks down hydrogen peroxide into water and oxygen.

Experimental procedure:

  1. Prepare test tubes containing different concentrations of catalase (serially diluted solutions containing a ground down catalase source, such as potato).
  2. Set up the experiment with a conical flask fit with a bung and glass tube leading to an upturned measuring cylinder filled with water.
  3. Pour hydrogen peroxide into the conical flask.
  4. Pour in one of the test tubes of catalase solution, start a timer, and mix.
  5. Record the volume of oxygen produced every 10 seconds.

Repeat the above procedure for all concentrations of catalase, recording your results.

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Initially, increasing enzyme concentration increases the rate of reaction because there are more active sites available to form enzyme–substrate complexes. With ample substrate available, the initial reaction rate increases linearly with enzyme concentration.

If the substrate is limited, increasing the enzyme concentration further will not increase the reaction rate, because substrate availability becomes the limiting factor. The reaction rate will have reached

A graph depicting the relationship between enzyme concentration and rate of reaction. The x-axis is labeled 'Enzyme concentration' and the y-axis is labeled 'Rate of reaction'. A red curve starts at the origin, increases steeply, and then levels off, approaching a horizontal asymptote labeled 'Vmax'. Annotations include: 'Rate of reaction increases proportionally to enzyme concentration' near the rising portion of the curve, and 'All active sites are occupied. The maximum number of enzyme-substrate complexes has formed. Increasing enzyme concentration does not affect reaction rate' near the plateau. The curve flattens as it reaches Vmax.
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Some enzymes require a non-protein component to function. A cofactor can temporarily bind to an enzyme, altering its tertiary structure and the shape of its active site to activate it.

Examples of cofactors include:

  • Inorganic ions – metal ions such as , or chloride ions bound to amylase
  • Coenzymes – organic molecules that bind temporarily, e.g. NAD, FAD
  • Prosthetic groups – organic or inorganic molecules that are tightly bound to the enzyme, e.g. zinc ions bound to carbonic anhydrase in red blood cells

Some cofactors help to stabilise the structure of the enzyme, whereas others take part in the reaction at the active site.

Cofactors can also help bind the substrate to the enzyme and are not changed or used up during the reaction.

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Coenzymes are small, organic molecules that help enzymes function by transferring chemical groups or electrons between reactions or by forming part of the active site. Although they are temporarily altered during reactions, they are continuously recycled.

Many coenzymes are derived from vitamins. For example:

  • Vitamin B5 (pantothenic acid) is a key component of coenzyme A.
  • Vitamin B3 (nicotinic acid) is used to produce the coenzymes NAD and NADP.
  • Vitamin B1 (riboflavin) is used to produce the coenzyme FAD.
Flowchart illustrating enzyme activation. At the top, an inactive enzyme with labeled active site does not bind with a substrate, indicated by a red cross and the label 'Substrate does not fit active site'. A cofactor and substrate are shown separately. An arrow points downward to the next stage where the cofactor binds to the enzyme, labeled 'Cofactor enables the substrate to bind to the enzyme’s active site'. The enzyme is now labeled as activated. The substrate is shown binding to the enzyme. Another arrow points downward to show the activated enzyme converting the substrate into products, depicted by two separate shapes labeled 'Products'.
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Inhibitors are molecules which stop enzymes from functioning or slow them down. They can bind to enzymes reversibly or irreversibly. There are two types of inhibitors:

  • Competitive inhibitors have a similar shape to the substrate and compete to bind to the enzyme’s active site. By forming enzyme–inhibitor complexes, competitive inhibitors reduce the formation of enzyme–substrate complexes.
  • Non-competitive inhibitors bind to the enzyme at an alternative site (or allosteric site), which alters the shape of the active site. This reduces the activity of the enzyme or prevents the substrate from binding.
The image shows two diagrams labeled 'Competitive inhibition' and 'Non-competitive inhibition.' In the competitive inhibition diagram, the left side shows an enzyme with active site labeled, alongside substrates and an inhibitor. An arrow points to the right side, where the inhibitor competes with substrates for the active site. In the non-competitive inhibition diagram, the left side shows an enzyme with substrates and an inhibitor. An arrow points to the right side, where the inhibitor binds at an alternative binding site, changing the shape of the enzyme's active site, preventing substrate binding.
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Competitive and non-competitive inhibitors decrease the reaction rate. At sufficiently high inhibitor concentrations, the reaction can cease entirely.

Increasing substrate concentration can counteract the effect of a competitive inhibitor, as more substrate molecules are available to collide with enzymes and form enzyme–substrate complexes.

Increasing substrate concentration does not restore the reaction rate in the presence of a non-competitive inhibitor, since the inhibitor changes the enzyme’s active site, preventing enzyme–substrate complex formation.

The graph has 'Rate of reaction' as the y-axis label and 'Substrate concentration' as the x-axis label. Three curves are plotted: a blue curve labeled 'No inhibitor' shows a steep increase and then plateaus; a purple curve labeled 'Competitive inhibitor (fixed quantity)' shows a less steep increase and also plateaus; a red curve labeled 'Non competitive inhibitor (fixed quantity)' shows a gradual increase and plateaus at a lower rate than the other two curves. The curves represent different scenarios of enzyme inhibition on the rate of reaction.
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Reversible inhibitors can regulate metabolic pathways to ensure reactions are tightly controlled, preventing any single enzyme from producing excessive amounts of a product or using up too many resources.

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Metabolic pathways can be controlled through end-product inhibition, where the final product of a metabolic pathway acts as a non-competitive, reversible inhibitor.

As the end-product accumulates, it binds to an alternative site on the initial enzyme, altering its active site and reducing or stopping its catalytic activity by decreasing the formation of enzyme–substrate complexes.

If the end-product concentration falls, it detaches from the enzyme, restoring the enzyme’s activity. This feedback loop allows catalysis to resume as product levels decrease.

A flowchart illustrating a biochemical pathway with inhibition. At the top, a box labeled 'Inhibition' connects downward with arrows to three boxes labeled 'Enzyme 1', 'Enzyme 2', and 'Enzyme 3'. Below them, another row of boxes labeled 'Substrate', 'Product 1', 'Product 2', and 'Product 3 (end-product)' are connected sequentially with rightward arrows. Each enzyme box has a downward arrow connecting to its corresponding product box. The 'Inhibition' box has arrows pointing to the lines connecting the enzymes to their respective products, indicating inhibition at those points.
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Irreversible inhibitors bind to an enzyme permanently. In living cells, this results in the complete inactivation of the enzyme, potentially stopping the biological reaction it catalyses.

To restore enzyme activity, a cell must produce more of the inhibited enzyme through gene transcription and translation.

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